(1)①O2+4e-+2H2O=4OH- ② 2Cl-+2H2O=Cl2↑+H2↑+2OH-③5Cl2+I2+6H2O=10HCl+2HIO3(2)①Fe-2e-=Fe2+ ②阴极,2CuSO4+2H2O=2Cu+O2↑+2H2SO4;减小
(1)甲为铁的吸氧腐蚀:正极:O2+4e-+2H2O=4OH- 负极:Fe-2e-=Fe2+乙是电解食盐水:2Cl-+2H2O=Cl2↑+H2↑+2OH-(2)甲为原电池,铁为负极:Fe-2e-=Fe2+;乙为电解硫酸铜的电解池;铁为阴极,总反应为:2CuSO4+2H2O=2Cu+O2↑+2H2SO4