(x+1)/(x+2)-1/(x+7)=(x+2)/(x+3)-1/(x+6)方程两边同时乘以(x+2)(x+7)(x+3)(x+6)得:(x+1)(x+7)(x+3)(x+6)-(x+2)(x+3)(x+6)=(x+2)(x+6)(x+2)(x+7)-(x+2)(x+7)(x+3)整理得:(x+2)(x+3)-(x+6)(x+7)=0即:x^2+5x+6-(x^2...
简便点说行不~~~~~O(∩_∩)O~~~~~~挑重点~~~
啊???这个是过程啊·····就是方程两边同时乘以最简公分母然后去括号移项合并同类项系数化1求解