已知(1,2)∈A∩B,A={(x,y)|y^2=ax+b},B={(x,y)|x^2-ay-b=0,则a=?b=?
已知(1,2)∈A∩B,A={(x,y)|y^2=ax+b},B={(x,y)|x^2-ay-b=0},则a=?b=?