高数---由通解求特解
设y1(x)是方程y'+p(x)y=0的特解,y2(x)是方程y'+p(x)y=Q(x)(Q(x)不等于0)的特解,C是任意常数,则y'+p(x)y=Q(x)的通解是
Ay1(x)+Cy2(x)BCy1(x)+y2(x)