CnH2n+(3n/2)O2=nCO2+nH2O
xL(3n/2)xLnxLnxL
CnH(2n-2)+(3m-1/2)=mCO2+(m-1)H2O
yL(3m-1/2)yLmyL(m-1)yL
x+y=1------①
nx+my=3.6------------②
nx+(m-1)y=3----------③
由②③得,
x=0.4y=0.6
∴L(烯烃):L(炔烃)=2:3
烯烃燃烧,前后体积相等.
0.4+0.6n=0.4n+0.4n
∴n=2∴烯烃为C2H4
同理,0.6+0.3(3m-1)=0.6m+0.6(m-1)
∴m=3∴炔烃为C3H4
好了,