1)a=3时,A={3};a≠3时,A={3,a},
而B={1,4},
所以a=3时,AUB={1,3,4},A∩B=Φ,
a=1时,AUB={1,3,4},A∩B={1},
a=4时,AUB={1,3,4},A∩B={4},
当a≠1且a≠3且a≠4时,AUB={1,3,4,a},A∩B=Φ.
2)因为(CuA)∩(CuB)=Cu(AUB)=Φ,A∩(CuB)={1,3,5,7},
因此CuB=U∩(CuB)=(AUCuA)∩(CuB)=(A∩CuB)U[(CuA)∩(CuB)]=ΦU{1,3,5,7}={1,3,5,7},
则B=Cu{1,3,5,7}={0,2,4,6,8,9,10}.