【解析】(1)2-溴丙烷在氢氧化钠的醇溶液中发生消去反应,生成丙烯、溴化钠和水,该反应的化学方程式为:CH3-CHBr-CH3+NaOHCH3-CH=CH2↑+NaBr+H2O;(2)1-溴丁烷在氢氧化钠的醇溶液中加热生成1-丁烯,反应方程式为:BrCH2(CH2)2CH3+NaOHCH2=CHCH2CH3↑+NaBr+H2O;1-丁烯与溴水发生加成,生成1,2-二溴丁烷,反应的化学方程式为:CH2=CHCH2CH3+Br2→BrCH2CHBrCH2CH3;【答案】(1)CH3-CHBr-CH3+NaOHCH3-CH=CH2↑+NaBr+H2O;(2)BrCH2(CH2)2CH3+NaOHCH2=CHCH2CH3↑+NaBr+H2O;CH2=CHCH2CH3+Br2→BrCH2CHBrCH2CH3;