解下列一元二次方程:(1)9(x-2)²-121=0(2)2(x-3)²=x(x-3)
(1)9(x-2)²-121=0
(2)2(x-3)²=x(x-3)
(3)x²-2倍的根号5x+1=0
(4)(x-1)²-5(x-1)+6=0