这个题目出得不伦不类,说是化简题吧,不像.说是方程吧,又没有等式.(x+2)/(x+1)-(x+3)/(x+2)-(x-4)/(x-3)+(x-5)/(x-4)=[(x+1)+1]/(x+1)-[(x+2)+1]/(x+2)-[(x-3)-1]/(x-3)+[(x-4)-1]/(x-4)=1+1/(x+1)-1-1/(x+2...
呵呵是化简再问一道若分式方程m(x-1)分之2(x+m)=-5分之8的解为x=-5分之一,则m的值为多少?另外会给你10分的哟
2(x+m)/[m(x-1)]=-8/5整理,得(4x+1)m=-5xm=-5x/(4x+1)x=-1/5代入,m=-5×(-1/5)/[4×(-1/5)+1]=5m=5