1.若x分之1-y分之1=2,则求x-xy-y分之3x+xy-3y=0的值.若x分之1-y分之1=2变形(y-x)/xy=2,(y-x)=2xy(3x+xy-3y)/(x-xy-y)=[3(x-y)+xy]/[(x-y)-xy]=(-6xy+xy)/(-xy-xy)=(-5xy)/(-2xy)=5/22.设x,y为实数,且x-y=3.求x乘根...
=(-6xy+xy)/(-xy-xy)这一步后面的括号里第一个-xy怎么搞的,y-x=2xy,那x-y不应该是-2xy吗?
]=(-6xy+xy)/(xy-3xy)=(-5xy)/(-2xy)=5/2
我也看错了,因该是x-xy-y=-xy+(x-y)=-xy-xy=-2xy我第一次的没有错
因该是x-xy-y=-xy+(x-y)=-xy-2xy=-3xy你理解的是对的