1.Thesumofndifferentnaturalnumbersislessthan50.thegreatestpossiblevalueofnis----
2.Letabetheaverageofalloddprimenumberslessthan50.Theinreger,mostclosetoais----
3.Iftwoevennaturalnumbersx,ysatisfyequationx的平方加100等于y的平方,x大于ythenx乘y等于----
1.Sincetherearesomecontroversies,Isuppose0doesnotbelongtonaturalnumbersinthiscase.Theanswerisquitestraightfoward,1+2+3+4+5+6+7+8+9=45.Ifweadd10,thenthesumwillexceed50.Sothegreatestpossiblenis9.
2.Firstofall,youcanlistalltheoddprimenumberslessthan50:3571113171923293137414347.Addthemup,andcalculatetheaverage.Theaverageaisequalto23.3.Thereforetheinteger,mostclosetoais23.
3.x^2+100=y^2,then(y-x)(x+y)=100,sincexandyarenaturalnumbers,x+y>0,yshouldbelargerthanx.Iamafraidthereiseithersomethingwrongwiththeproblemoratypingmistake.
Youcanshowmetheoriginalversionoftheproblem3.