(2013•遵义模拟)观察下面方程的解法:x4-13x2+36=0.解:原方程可化为(x2-4)(x2-9)=0,∴(x+2)(x-2)(x+3)(x-3)=0,∴x+2=0或x-2=0或x+3=0或x-3=0,∴x1=2,x2=-2,x3=3,x4=-3.请根据此解法求出方程x2-3|x|+2=0的解为______.