已知数列{an}是首项为a,且公比q不等于1的等比数列.Sn是前项的和,a1,2a7,3a4成等差数列.
<1>证明12S3,S6.S12-S6成等差数列:
<2>Tn=a1+2a4+3a7+.+na3n-2