可以直接计算的.设X^T=(x1,x2,...,xn),Y^T=(y1,y2,...,yn),An=det(E+X*Y^T)1+x1y1x1y2x1y3...x1ynx2y11+x2y2x2y3....x2yn按第1列分成两个行列式=x3y1x3y21+x2y3.x3yn.xny1xny2xny3.1+xnyn1x1y2x1...
没想到简单的办法,感觉要复杂点Bn=det(E+X*Y^T-λE)=det((1-λ)E+X*Y^T),用上面同样的作法.Bn=(1-λ)B(n-1)+x1y1(1-λ)^(n-1)=(1-λ)[(1-λ)B(n-2)+x2y2(1-λ)^(n-2)]+x1y1(1-λ)^(n-1)=(1-λ)^2B(n-2)+x2y2(1-λ)^(n-1)+x1y1(1-λ)^(n-1)=.......=(1-λ)^n+xnyn(1-λ)^(n-1)+...+x2y2(1-λ)^(n-1)+x1y1(1-λ)^(n-1)=(1-λ)^(n-1)[1-λ+x1y1+x2y2+...+xnyn]特征值为n-1个1和1+x1y1+x2y2+...+xnyn